Ch3coo c 2 h 5 + naoh

bimolecular reaction II order reaction both 'a' and 'b' pseudo unimolecular reaction

Solution : In this `R prop` [Ester] `[NaOH]`
Hence the order of reaction is 2 . And two molecules involved so it is bimolecular .

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(i) CH3COOC2H5+NaOH →  CH3COONa + C2H5OH
(ii) CH3COOH+NaOH → CH3COONa + H2O
(iii) C2H5OH+CH3COOH 

Ch3coo c 2 h 5 + naoh
  CH3COOC2H5 + H2O

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