How many 5 letter words can be formed out of 10 consonants 4 vowels such that each contains 3 different consonants and 2 different vowels?
1) 24800 Show
2) 25100 3) 25200 4) 25400 Answer: (3) 25200 Solution: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C3 x 4C2) = 210. Number of groups, each having 3 consonants and 2 vowels = 210. Each group consist of 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 120 Required number of ways = (210 x 120) = 25200
Post your comments here:Name *: Email : (optional) » Your comments will be displayed only after manual approval. How many 5 letter words can be formed from 10 consonants and 4 vowels?Each group contains 5 letters. = 5! = 120.
How many words can be formed out of 5 different consonants and 4 vowels if each word is to contain 3 consonants and 2 vowels?D. 7200. Hint: The number of ways a word can form from $5$ consonants by using $3$ consonants $ = $ ${}^5{C_3}$ and from $4$ vowels by using $2$ vowels $ = $${}^4{C_2}$, hence the number of words can be $ = {}^5{C_3} \times {}^4{C_2} \times {}^5{P_5}$.
How many words of 5 letters each can be formed each containing 3 consonants and 2 vowels?So, total number of words = 5C2× 17C3×5! =816000.
How many words of 4 consonants and 4 vowels can be formed out of 8 consonants and 5 vowels?Detailed Solution
But all these five alphabets can permute among themselves = 5! ∴ The required result will be 40320.
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